Answer:
c. between 0.01 and 0.001
Explanation:
Given :
n = 40
x = 12
P = 0.5
H0: p = 0.50
Ha :p < 0.50
Sample proportion, p' =

This is a lower tailed test
Standard deviation will be:

For test statistic :

p-value wil be:
(P < Zobserved) = (P < -2.53)
From the normal distribution table,
NORMSDIST(-2.53) = 0.0057060 ≈ 0.0057
p-value = 0.0057
Therefore the p-value is between
c. between 0.01 and 0.001.