Question

2 ton car that starts from rest under the action of traction engine for 30 seconds gains speed 52 km / h. the coefficient of friction between the wheels of the car and the road is 0.02. find: the work done by the traction of the engine and the friction beam on the car at this time​

Answer 1

1 m/s=3.6km/her

56km/hr=?

=56km/hr×1m/s/3.6km/her

velocity is 15.5m/s

Step-by-step explanation:

w=fs

a=v/t

a=15.5m/s/30s

a=465m/s^2

w=fs

w=0.02×