Answer:
753.7°C
Step-by-step explanation:
Step 1:
Data obtained from the question. This includes the following:
Initial volume (V1) = 15L
Initial temperature (T1) = 35°C = 35°C + 273 = 308K
Final volume (V2) = 50L
Final temperature (T2) =..?
Step 2:
Determination of the new temperature of the Neon gas.
The new temperature of the neon gas can be obtained by using Charles' law since the pressure is constant. This is illustrated below:
V1/T1 = V2/T2
15/308 = 50/T2
Cross multiply to express in linear form
15 x T2 = 308 x 50
Divide both side by 15
T2 = (308 x 50)/15
T2 = 1026.7K
Step 3:
Conversion of 1026.7K to celsius.
T(°C) = T(K) – 273
T(°C) = 1026.7K
T(°C) = 1026.7 – 273
T(°C) = 753.7°C
Therefore, the new temperature of the Neon gas is 753.7°C