Question

The distance from Charlotte to Asheville is about 120 miles. If R.C. has two hours to make the trip, but drives 50 mph for the first 60 miles, how fast must R.C. go on the second half of the trip to reach Asheville in time?

A. 70 mph
B. 75 mph
C. 77.2 mph
D. none of these

Answer 1

The answer is b

Hope it helps

Answer 2

B. 75 mph

Explanation:

d - distance

v - velocity

t - time

d = 120 miles

t = 2 hrs

1st 60 miles :

`v = (d)/(t)`

`t = (d)/(v)`

`t = (60)/(50)`

`t = 1.2 \: hrs`

`t = 1.2 * 60`

`t = 72 \: minutes`

2nd 60 miles:

It took 72 minutes for him to travel the first 60 miles. To get the remaining time:

`t = 120 - 72`

`t = 48 \: minutes`

`t = 0.8 \: hrs`

For the Velocity:

`v = (d)/(t)`

`v = (60)/(0.8)`

`v = 75 \: mph`