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7 votes
Find the equation of the tangent to the curve y = 4x³- 5x² + x - 3 at the point where it crosses the y axis.​

User Pini Reznik
by
3.1k points

2 Answers

23 votes
23 votes

Answer:

-3

Explanation:

put x= 0

User Dmitry Shechtman
by
2.6k points
15 votes
15 votes

Answer:

y = x-3

Explanation:

When the graph of this equation crosses the y - axis , the value of x is = 0.

sub in zero to find this y value = -3

so the point is (0, -3)

Now find the drivative of this equation....the derivative tells you the slope of the original graph at any given point

derivative = 12x^2-10x+1 this , when x = 0 shows slope = 1

the equation then becomes y = (1) x -3 or just y = x-3

See image below

Find the equation of the tangent to the curve y = 4x³- 5x² + x - 3 at the point where-example-1
User Bike
by
2.6k points