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Cos (theta) = square of 2 / 2, and 3*pi/2 < theta < 2*pi, evaluate sin (theta) and tan (theta)

Cos (theta) = square of 2 / 2, and 3*pi/2 < theta < 2*pi, evaluate sin (theta) and tan (theta)
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Cos (theta) = square of 2 / 2, and 3*pi/2 < theta < 2*pi, evaluate sin (theta) and tan (theta)

Cos (theta) = square of 2 / 2, and 3*pi/2 < theta < 2*pi, evaluate sin (theta-example-1
User Sergey Ilinsky
by
8.5k points

1 Answer

3 votes

Answer: negative square root of two over 2 and tan theta is -1

Explanation:

Did it on edge and got it right

User Laalto
by
7.8k points
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