Question

2n (2n+2) (2n+4) how do solve that

Answer 1

8n^3+24n^2+16n

Explanation:

First of all, you'd use the FOIL method and multiply the two terms together. (2n+2) and (2n+4). 2nx2n is 2n^2. Then, 2nx4 is 8n. Then you multiply 2 into the second term, 2x2n=4n and 2x4=8. Last of all, you multiply the coefficient (2n) into the expression (4n^2+8n+4n+8) or simplified (4n^2+12n+8). 2n times 4n^2 is 8n^3, then 2n times 12n is 24n^2 and last of all 2nx8 is 16n making your final expression 8n^3+24n^2+16n

Answer 2

n = 0, -1, -2

Explanation:

Set the equation equal to zero.