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A 10-kg medicine ball is thrown at a velocity of 15 m/s to a 65-kg person who is at rest on ice. The

person catches the ball and subsequently slides with the ball across the ice. Determine the velocity of
the person and the ball after the collision.

User Daniel Jackson
by
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1 Answer

7 votes
7 votes

Answer:

2 m/s

Step-by-step explanation:

Conservation of momentum:

momentum after catch = momentum of system before catch

before catch . momentum = 10 kg * 15 m/s = 150 kg-m/s

after catch m = 65 + 10 = 75 kg

75 kg * v = 150 kg-m/s

v = 2 m/s