118k views
5 votes
How does the mean absolute deviation (MAD) of the data in set 1 compare to the mean absolute deviation of the data in set 2?

Set 1: 82, 80, 90
Set 2: 82, 80, 60, 90

User Robpvn
by
8.4k points

2 Answers

3 votes

Answer:

Mean Absolute deviation for (set 1): 4

Mean Absolute deviation for (set 2): 9

Set 2 has a lower (MAD) mean absolute deviation that Set 1.

Explanation:

(set 1)

Mean: 80 + 82 + 90 = 252/3 = 84

84 - 80 = 4

84 - 82 = 2

84 - 90 = 6

Mean Absolute Deviation: 2 + 4 + 6 = 12/3 = 4

(set 2)

Mean: 60 + 80 + 82 + 90 = 312/4 = 78

78 - 60 = 18

78 - 80 = 2

78 - 82 = 4

78 - 90 = 12

Mean Absolute Deviation: 2 + 4 + 12 + 18 = 36/4 = 9

User Yulian
by
7.9k points
2 votes

Answer:

Answer: Second option: The MAD of set 1 is 5 less than the MAD of set 2.Set

Explanation:

1: 82, 80, 90

n=3

Mean=(82+80+90)/3=252/3→Mean=84

Absolute Value: AV

MAD=[AV(82-84)+AV(80-84)+AV(90-84)]/3

MAD=[AV(-2)+AV(-4)+AV(6)]/3

MAD=(2+4+6)/3

MAD=12/3

MAD=4

Set 2: 82, 80, 60, 90

n=4

Mean=(82+80+60+90)/4=312/4→Mean=78

Absolute Value: AV

MAD=[AV(82-78)+AV(80-78)+AV(60-78)+AV(90-78)]/4

MAD=[AV(4)+AV(2)+AV(-18)+AV(12)]/4

MAD=(4+2+18+12)/4

MAD=36/4

MAD=9

MAD of set 2 - MAD of set 1 = 9-4=5

User Phil Lello
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories