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A conducting wire has a length of 3m and a resistance of 0.35 Ώ , when a potential difference is applied to the ends of the wire, a current of the 1.8 A is produced in it. What is the magnitude of the
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A conducting wire has a length of 3m and a resistance of 0.35 Ώ , when a potential difference is applied to the ends of the wire, a current of the 1.8 A is produced in it. What is the magnitude of the electric field inside the wire?

User Stephen Watkins
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Answer: E = IR/L

SO

E= 1.8A*0.35Ω/3m=0.21

Step-by-step explanation:

User Jessieloo
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