Answer:
t = - 3, t = - 1
Explanation:
Given
h(t) = t² + 4t + 3
To find the zeros equate h(t) to zero, that is
t² + 4t + 3 = 0
Consider the factors of the constant term (+ 3) which sum to give the coefficient of the t- term
The factors are + 3 and + 1, since
3 × 1 = 3 and 3 + 1 = 4, thus
t² + 4t + 3 = (t + 3)(t + 1) = 0
Equate each factor to 0 and solve for t
t + 3 = 0 ⇒ t = - 3
t + 1 = 0 ⇒ t = - 1
smaller zero is t = - 3
larger zero is t = - 1
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