Answer:
C. (1,0)
Explanation:
If we make use of a parabolic reflecting mirror and a light source.
Given thar the equation of parabolic mirror is Y2 = 4ax
The given data in the problem is x = 1 and y = 2
So subject value is y2 = 4ax
4 = 4 a (1)
a = 1
So x = 1
thus focus is at (x, y) = (1,0)
Therefore, option C is correct answer.