204k views
4 votes
Calculate the approximate temperature of a 0.50 mol sample of gas at 0.99 atm and a

volume of 12 L. (Hint: Convert your final answer back to Celsius)

User Donnette
by
6.0k points

1 Answer

2 votes

Answer:

The approximate temperature of a 0.50 mol sample of gas at 0.99 atm and a volume of 12 L is 16.61 °C

Step-by-step explanation:

An ideal gas is a theoretical gas that is considered to be made up of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures. The equation of state that describes a gas under these conditions is called the equation of state of an ideal gas.

That is, the state of a quantity of gaseous matter is formulated based on four different variables: pressure, volume, temperature and number of moles of gas. The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

In this case, you know:

  • P= 0.99 atm
  • V= 12 L
  • n= 0.50 mol
  • R= 0.082
    (atm*L)/(mol*K)
  • T=?

Replacing:

0.99 atm* 12 L= 0.50 mol* 0.082
(atm*L)/(mol*K)* T

Solving:


T=(0.99 atm* 12 L)/(0.50 mol* 0.082(atm*L)/(mol*K))

T= 289.76 °K

Being 273,15°K=0°C, the temperature 289.76°K=16.61°C

The approximate temperature of a 0.50 mol sample of gas at 0.99 atm and a volume of 12 L is 16.61 °C

User PaulCrp
by
6.3k points