2 Answers

Stefan J · Answer 1 · 2021-08-24T11:34:31+0000

We have been given an equation
$55^2=50^2+35^2-2(50)(35)\text{cos}(A)$ . We are asked to find the values of
$\text{cos}(A)$ .

First of all, we will square the terms.

$3025=2500+1225-3500\text{cos}(A)$

$3025=3725-3500\text{cos}(A)$

Now we will subtract 3725 from both sides as:

$3025-3725=3725-3725-3500\text{cos}(A)$

$-700=-3500\text{cos}(A)$

Switch sides:

$-3500\text{cos}(A)=-700$

Upon dividing both sides by
, we will get:

$\frac{-3500\text{cos}(A)}{-3500}=(-700)/(-3500)$

$\text{cos}(A)=(7)/(35)$

$\text{cos}(A)=(1)/(5)$

$\text{cos}(A)=0.2$

Therefore, the values of
$\text{cos}(A)$ is 0.2.

Please log in or register to add a comment.