Question

A rectangle has a length 6 m less than twice its width. When 3 m are added to the width, the resulting figure is a square with an area of 144 m2. Find the dimensions

of the original rectangle.

Answer 1

Original width = 9m and original length = 12m

Explanation:

Let original width be
`w` and original length be
`l`.

According to question statement:

`l = 2 * w -6 ...... (1)`

When 3m added to width, the resulting figure becomes square with area 144
`m^(2)`, also area of a square =
`side^(2)`

`\Rightarrow (w+3)^(2) = 144\\\Rightarrow (w+3) = 12\\\Rightarrow w = 9m`

Putting value of
`w` in equation (1):

`\Rightarrow l = 2 * 9 - 6\\\Rightarrow l = 12m`

Hence, original dimensions of rectangle are:

Length = 12m

Width = 9m