Question

-3 and -1/2 form quadratic polynomial​

Answer 1

2x² + 7x + 3 = 0

Explanation:

`\sf \text{Sum = -3 + $((-1)/(2))$}`

`\sf = (-3*2)/(1*2)-(1)/(2)\\\\=(-6)/(2)-(-1)/(2)\\\\=(-7)/(2)`

`\sf \text{Product =$-3*(-1)/(2)$}`

`= (3)/(2)`

Quadratic polynomial:

`\boxed{x^(2)-sum *x+product = 0}`

`x^(2)- \left((-7)/(2)\right)x+(3)/(2)=0\\\\x^(2) + \left((7)/(2)\right)x+(3)/(2)=0\\`

Multiply the entire equation by 2

`2*x^(2) + 2*(7)/(2)x +2*(3)/(2)=0`

2x² + 7x + 3 = 0