Answer:
Explanation:
Solving system of symultaneous equation:
Let the cost of one roll of plain wrapping pair = x
Let the cost of one shiny wrapping paper = y
Amanda:
Cost of 3 rolls of plain paper + cost of 3 rolls of shiny paper = $ 60
3*x + 3*y = 60
3x + 3y = 60 ------------------(I)
Molly:
Cost of 1 roll of plain paper + cost of 9 rolls of shiny paper = $ 132
x + 9y = 132 ---------------------(II)
x = 132 - 9y ---------------(III)
Substitute x = 132 -9y in equation (I)
3*(132-9y) + 3y = 60
3*132 - 3*9y + 3y = 60
396 - 27y + 3y = 60
Combine like terms
396 - 24y = 60
Subtract 396 from both sides
-24y = 60 - 396
-24y = -336
Divide both sides by (-24)
y = -336/(-24)
Now, substitue y = 14 in equation (III)
x = 132 - 9*14
= 132 - 126
cost of one roll of plain wrapping paper = $ 6
Cost of one roll of shiny wrapping paper = $ 14