Answer:
Answer is 13.
Explanation:
EQ 1: y = 2x^2-x-2
EQ2: y = x^2+3x -5
Set the two equation equal to each other:
2x^2-x-2 = x^2+3x -5
Simplify:
x^2 -4x +3 = 0
(x - 3 ) (x - 1) = 0
Solutions:
x = 3 and x= 1
Plug these values into each of the original equations and see which on gives you the highest value.
Solution set:
y={13, -1, 13, -1}
Answer is 13