Question

What is an equation of the line that passes through the points (-8, 1) and (7, 1)

Answer 1

ANSWER: y = 1

STEPS:

first, find the slope by using the formula

which is also represented as m

`m = (y2 - y1)/(x2 - x1)`

where from point (-8, 1) x1 is -8 and y1 is 1

then from point (7, 1) x2 is 7 and y2 is 1

so we substitute into the formula

`(1 - 1)/(7 - ( - 8)) = (0)/(7 + 8) = (0)/(15)`

`m = (0)/(15)`

Then we solve for the equation of the line by using the formula

`(y - y1) = m(x - x1)`

but we have only y1, m and x1 so we substitute given us

`(y - 1) = (0)/(15) (x - ( - 8))`

but also, we must get rid of the fraction 0/15

so we multiply through by the denominator 15

`15 * (y - 1) = 15 * (0)/(15) (x - (8))`

we get

`15(y - 1) = 0(x - ( - 8))`

now we expand all brackets

`15y - 15 = 0`

but we want the equation so we make y stand alone

`15y = 15 \\ \\ (15y)/(15) = (15)/(15) \\ \\ y = 1`

the equation of the line is y=1