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Please can someone help me with this?​

Please can someone help me with this?​-example-1
User Caley
by
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2 Answers

5 votes

Answer:

2243.7 cm^2 to the nearest tenth.

Explanation:

Total volume = volume of cylinder + volume of the cone

= πr^2h + 1/3πr^2(59 - h) where h is the height of the cylinder.

So 6622 = π(7)^2h + 1/3π(7)^2(59 - h)

49πh + 49/3 π * 59 - 49/3 π h = 6622

49πh - 49/3 π h = 6622 - 49/3 π * 59

h( 49π - 49/3 π) = 6622 - 49/3 π * 59

h = (6622 - 49/3 π * 59) / ( 49π - 49/3 π)

h = 35.026 cm = height of the cylinder.

So the height of the cone = 59 - 35.026 = 23.974.

Next we find the slant height of the cone (L).

L^2 = 7^2 + 23.974^2

= 623.753

L = 24.975

The surface area of the whole solid

= surface area of the exposed cylinder + lateral surface area of the cone

= πr^2 + 2π*h + πrL

= π(7)^2 + 14π*35.026 + π(7)*24.975

= 2243.69 cm^2.

User Ziem
by
2.8k points
12 votes

Explanation:

all answer doesn't adjust. please use the formula and do it. (h=height of cylinder and h1 =height of cone)

Please can someone help me with this?​-example-1
Please can someone help me with this?​-example-2
User CubaLibre
by
3.7k points