Question

This is your code. >>> A = [21, 'dog', 'red'] >>> B = [35, 'cat', 'blue'] >>> C = [12, 'fish', 'green'] >>> e = [A,B,C] How do you refer to 'green'? e(2, 2) e(2, 2) e(2)(2) e(2)(2) e[2][2] e[2][2] e[2, 2] e[2, 2]

Answer 1

To refer to 'green', you'd use the notation `e[2][2]`. This accesses the third list in the list `e` (index 2) and then retrieves the item at index 2 within that list.

Step-by-step explanation:

In the given code snippet, the variable `e` is a list containing three lists: A, B, and C. Each inner list holds three elements. To access 'green', which is in the third position of the third inner list, you use `e[2][2]`.

Breaking this down, `e[2]` refers to the third inner list in `e`. This gives us `[12, 'fish', 'green']`. Then, to extract 'green', you use `[2]` on this inner list, which retrieves the element at index 2 within that list, resulting in 'green'.

Notation like `e(2, 2)` or `e(2)(2)` is incorrect for accessing elements in a nested list in Python. Square brackets (`[]`) are used to access elements in a list by index. So, the correct way to access 'green' within the nested lists of `e` is to use the square bracket notation: `e[2][2]`. Other variations like `e(2, 2)` or `e(2)(2)` would not work in Python syntax for accessing elements within nested lists.

Answer 2

So the final list is

• e=[A,B,C]

Then

• e=[[21,'dog','red'],[35,'Cat','blue'],[12,'fish','green']]

green is inside a nested list of index 2

• C is at index 2 also

Hence required reference is

• e[2][2]