Explanation:
Sum
(4-3i)+(-4+5i)
=4-4-3i+5i
=0+2i
=2i
Product
(4-3i)(-4+5i)
=4(-4)-3i(-4)+4(5i)-3i(5i)
=(-16)+7i+20i-15i²
-16+27i-15(-1) [i²=(-1)]
=27i-16+15
=27i-1
=(-1+27i)
I hope it helped you
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