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Find the sum and product of the complex numbers 4-3 i and - 4 + 5 i ​

1 Answer

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Explanation:

Sum

(4-3i)+(-4+5i)

=4-4-3i+5i

=0+2i

=2i

Product

(4-3i)(-4+5i)

=4(-4)-3i(-4)+4(5i)-3i(5i)

=(-16)+7i+20i-15i²

-16+27i-15(-1) [i²=(-1)]

=27i-16+15

=27i-1

=(-1+27i)

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