Question

Consider the number 4n , where n is a natural number. Check whether there is any value of e N for which 4n ends with the digit zero

Answer 1

Answer: 25
Explanation: Yes, if we take n=25, then 4n=100, which ends with a zero
Thus, 25 is ONE SUCH value

Answer 2

ANSWER:

No,
`{4}^(n)` for any value of n cannot end in 0.

Explanation:

Prime factorisation of 4:

4 = 2 × 2

As seen,

5 is not a prime factor of 4.

Therefore,
`{4}^(n)` for any value of n cannot end in 0.