Question

Examine the diagram and information to answer the question.

A circle with its center at (negative 3, 0) and with a radius of 4 units.

What is the equation of the circle?

(x−3)2+y2=16

(x+3)2+y2=16

(x−3)2+y2=4

(x+3)2+y2=4

Answer 1

(x + 3)² + y² = 16

Explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (- 3, 0 ) and r = 4, thus

(x - (- 3))² + (y - 0)² = 4², that is

(x + 3)² + y² = 16