Question

Imagine a SCUBA diver is 50 m below the surface of water where they experience 72.0 psi of pressure. The diver exhales a bubble of air that has a volume of 10.0mL at 72.0 psi. When the bubble reaches the surface of water it has a volume of 49.0 mL. What is the pressure at the surface of the water?

Answer 1

14.7 Psi

Step-by-step explanation:

The following data were obtained from the question:

Initial pressure (P1) = 72.0 Psi

Initial volume (V1) = 10mL

Final volume (V2) = 49mL

Final pressure (P2) =..?

Next, we shall calculate the new pressure by applying the Boyle's law equation as illustrated below:

P1V1 = P2V2

72 x 10 = P2 x 49

Divide both side by 49

P2 = (72 x 10 ) / 49

P2 = 14.7 Psi

Therefore, the pressure of the bubble of air at the surface of the water is 14.7 Psi