Question

Examine the diagram and information to answer the question.

⨀C lies on the coordinate plane with its center at C(2,−2).
The radius of ⨀C is 4 units.
Point P appears to lie on ⨀C at (6,−2).
Circle C and point P in a coordinate plane as described in the text.


What is the equation for ⨀C?

(x−6)2+(y+2)2=4

(x−6)2+(y+2)2=16

(x−2)2+(y+2)2=16

(x−2)2+(y+2)2=4

Answer 1

Equation of circle
(x-h)^2 + (y-k)^2 = r^2
I believe it is
(x-2)^2 + (y+2)^2 = 16