Question

Please help

*The information in the table below gives information about energy use in a typical house.* ~A typical house in the United States uses about 10,900kWh (kilowatt-hour) of electricity per year.
1 TWh (terawatt-hour) =1×10^6 GWh (gigawatt-hour) =1×10^9kWh (kilowatt-hour).~

The world’s largest hydroelectric power plant is the 22.5 gigawatt ( GW ) Three Gorges Dam in China. It produces about 90TWh of electricity each year. If a hydroelectric plant with the same capacity as the Three Gorges Dam was built in the United States, calculate how many houses such a plant would be able to provide the electricity for in a year. Show your work.

Answer 1

the number of houses ≈ 8.25 million houses

Step-by-step explanation:

Given that:

A typical house in the United States uses about 10,900 kWh,

1 TWh (terawatt-hour) =1×10^6 GWh (gigawatt-hour) =1×10^9kWh (kilowatt-hour)

The three Gorges Dam in China produces about 90TWh of electricity each year. If it was to to be built in the United states, the number of houses such a plant would be able to provide the electricity for in a year is given as:

Number of houses = Amount of electricity produced in a year / amount of electricity used by each house.

Number of houses = 90 TWh / 10,900 kWh = 90 × 10⁹ kWh / 10,900 kWh = 8256881

Therefore the number of houses ≈ 8.25 million houses