Question

If 13.5 moles of oxygen are reacted with an excess of ammonia, how many moles of NO and of H2O are formes given the following equation. 4NH3+5O2 =4NO + 6H2O

Answer 1

Step-by-step explanation:

NO=10.8Mol

H2O=16.2Mol

4NH3 + 5O2 --> 4NO + 6H2O

5Mol of O2 Produce 4Mol of NO

Therefore 13.5Mol of O2 produce NO = (13.5/5)x4 = 10.8

H2O Mol = (13.5/5) x 6 = 16.2