Question

What did I do wrong?!!! Help pls!!

Answer 1

you have done mistake while putting the numbers on the formula.

Explanation:

-(-6)

+6

Answer 2

Quadratic equations : ax² +bx +c

b² -6b +5= -4

b² -6b +5 +4=0

b² -6b +9=0

Instead of x, the algebraic term is b.

So the coefficient of b², a, is equal to 1

coefficient of b, b, is equals to -6

and the constant c is 9.

Note that the value of b (coefficient of b term) is -6 not 6.

The formula you wrote is correct however when you substitute the value of b in "-b", it should have been -(-6) so you would get 6 instead.

`b = \frac{6 + \sqrt{( - 6)^(2) - 4(1)(9)}} \: or \: b = \frac{6 - \sqrt{( - 6)^(2) - 4(1)(9)(1)}} \\ \\b = (6 + √(0) )/(2) \: or \: b = (6 - √(0) )/(2) \\ b = (6)/(2) \: or \: b = (6)/(2) \\ b = 3 \: \: or \: b = 3`

Thus the answer should be b=3