Answer:
option D
Step-by-step explanation:
Given,
V₁ = 285 L
P₁ = 530 mm Hg
Standard pressure
P₂ = 760 mm Hg
V₂ = ?
Using relation between pressure and volume
![(P_1)/(V_2)=(P_2)/(V_1)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/crdlb8t77zpz4ko4xrihoiypynfqilqyho.png)
![(530)/(V_2)=(760)/(285)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/tmesdspik1oyb1qw99muewxh58y7nlztju.png)
![V_2 = 198.75\ L](https://img.qammunity.org/2021/formulas/chemistry/middle-school/74wf8ssmd4p2zftjk2w32q7mlmr326w6s6.png)
Hence, volume of the propane at standard pressure is equal to 198.8 L.
Hence, the correct answer is option D.