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What is the axis of symmetry of h(x)= 5x^2+40x+ 64?
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What is the axis of symmetry of h(x)= 5x^2+40x+ 64?

User Josh Kodroff
by
6.6k points

2 Answers

5 votes

Answer: x=-4

Explanation:

User Mohur
by
6.4k points
5 votes

Answer:

Axis of symmetry is x = -4

Explanation:

h(x)= 5x^2+40x+ 64

Use the formula for axis of symmetry: x = -b/(2a)

Here, a = 5, b = 40, c = 64

so

x = -40/(2*5) = -40/10 = -4

Axis of symmetry is x = -4

User Droidx
by
6.6k points
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