What is the axis of symmetry of h(x)= 5x^2+40x+ 64?

Question

asked Jun 10, 2021 169k views

2 Answers

Droidx · Answer 1 · 2021-06-17T08:36:58+0000

Answer:

Axis of symmetry is x = -4

Explanation:

h(x)= 5x^2+40x+ 64

Use the formula for axis of symmetry: x = -b/(2a)

Here, a = 5, b = 40, c = 64

so

x = -40/(2*5) = -40/10 = -4

Axis of symmetry is x = -4