Question

In a production turning operation, the foreman has decreed that a single pass must be completed on the cylindrical workpiece in 5.0 min. The piece is 400 mm long and 150 mm in diameter. Using a feed = 0.30 mm/rev and a depth of cut = 4.0 mm, what cutting speed must be used to meet this machining time requirement?

Answer 1

V = 125.7m/min

Step-by-step explanation:

Given:

L = 400 mm ≈ 0.4m

D = 150 mm ≈ 0.15m

T = 5 minutes

F = 0.30mm ≈ 0.0003m

To calculate the cutting speed, let's use the formula :

`T = (pi* D * L)/(V*F)`

We are to find the speed, V. Let's make it the subject.

`V = (pi* D * L)/(F*T)`

Substituting values we have:

`V = (pi* 0.4 * 0.15)/(0.0003*5)`

V = 125.68 m/min ≈ 125.7 m/min

Therefore, V = 125.7m/min