Question

Write a function that accepts an integer parameter and returns its integer square root (if it exists). The function should throw an exception if it is passed an integer that is not a perfect square. Do not handle the exception in the function, but instead create the exception handler in main. Make the exception a new exception class which your program creates. Demonstrate the function with a driver program that passes the function the numbers 0 through 25, then prints whether or not the number is a perfect square. (A "perfect square" is a whole number whose square root is also a whole number.)

Answer 1

See explaination

Step-by-step explanation:

// Include the necessary header files.

#include <iostream>

#include <exception>

#include <cmath>

using namespace std;

// Definition of the function.

int square_root(int n)

{

// Check whether n is less than 0.

if(n < 0)

// Throw exception.

throw domain_error("Supplied integer is negative!");

// check whether n is equal to 0;

else if(n == 0)

// Throw 0.

throw 0;

// Declare a variable and assign value.

double squ_root = sqrt(n);

// // Declare a variable and assign value.

int squ_root_int = (int)squ_root;

// compare values

// check whether the values are equal or not.

if(squ_root != squ_root_int)

// Throw exception.

throw invalid_argument("Supplied integer is not a perfect square !");

// return the value.

return squ_root_int;

}

// Declare the main function.

int main()

{

// declare variables.

int n;

int squ_root;

// Prompt the user to enter the number.

cout << "Enter a number: ";

cin >> n;

// start the try block.

try

{

// call to the function.

squ_root = square_root(n);

// Display the statement on console.

cout << "Square root is " << squ_root << endl;

}

// start the catch block.

catch(domain_error e)

{

// Display the statement on console.

cout << "Error: " << e.what() << endl;

return -1;

}

// Start the catch block

catch (int y)

{

// check whether y is equal to zero or not.

if(y == 0)

{

// Display the statement on console.

cout << "Error: Supplied integer is zero !" << endl;

return -2;

}

}

// Start the catch block

catch(invalid_argument e)

{

// Display the sstatement.

cout << "Error: " << e.what() << endl;

return -3;

}

// Return the value.

return 0;

}

Answer 2

Check the explanation

Step-by-step explanation:

#include <iostream>

#include <cmath>

#include <math.h> //Not sure about including math.h

using namespace std;

int sqrt4(const int m)

{

int i=0;

const int q=0;

while( (i*i) <= m )

{

if(i*i==m)

{

q++;

return i;

}

else

{

i++;

}

}

if(q==0)

{

throw "not a perfect square!";

}

}

int M1 (int x){

cout << "Number: " << x << endl;

x = sqrt(x);

cout << "Number's square root: " << x << endl;

return x;

}

void main (){

int y = 4; // Program currently uses 4 in calculations

M1 (y);

}