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A steam power plant receives heat from a furnace at a rate of 280 GJ/h. Heat transfer to the surrounding air from the steam as it passes through the pipes and other components are estimated to be about 8 GJ/h. If the waste energy is transferred to the cooling water at a rate of 145 GJ/h, determine the (a) net power output and (b) thermal efficiency of this power plan

User Gilfoyle
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Answer:

a)
\dot W = 35.278\,MW, b)
\eta_(th) = 45.357\,\%

Step-by-step explanation:

a) The net power output of the plant is:


\dot W = \left(280\,(GJ)/(h)-145\,(GJ)/(h) - 8\,(GJ)/(h) \right)\cdot \left(1000\,(MJ)/(GJ) \right)\cdot \left((1)/(3600)\,(h)/(s) \right)


\dot W = 35.278\,MW

b) The thermal efficiency of the power plant is:


\eta_(th) = (280\,(GJ)/(h)-145\,(GJ)/(h)-8\,(GJ)/(h) )/(280\,(GJ)/(h) ) * 100\,\%


\eta_(th) = 45.357\,\%

User Emre Colak
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