Answer:
Step-by-step explanation:
It is a problem based on simple harmonic motion and friction . maximum friction possible between large block and mass m is µ mg . During SHM , maximum acceleration is ω² A and force is mω² A .
friction must exceed it so that mass m may not slip over it during motion . so
µ mg ≥ mω² A
µ ≥ mω² A / mg
smallest value of µ
= mω² A / mg
= ω² A /g