Answer: Ksp (Ba(IO3)2)= 4.34*10^-9
Step-by-step explanation:
Total solution Volume : 15 mL = 0.015 L
moles of I3- = 20.55*10^-4 *0.015 L = 3.0825 *10^-5 moles
1 mol of IO3- gives 3 moles of I3- ===> mol of IO3- = 3.0825 *10^-5 moles/3 = 1.0275 *10^-5 moles
concentration of IO3- in original sample : 1.0275 *10^-5 mole/ 0.005 L = 0.002055 M
concentration of Ba2+ in original sample : 0.002055 M/2 = 0.0010275 M
Ksp (Ba(IO3)2) = [Ba2+] [IO3- ]2 = 4.34*10^-9