Question

A spoiler used on race cars to produce a negative lift, thereby providing a better traction. The lift coefficient for the spoiler is 1.1,and the coefficient of friction between the wheels and the pavement is 0.6. If the race car travels with a speed of 200 mph, by how much would the spoiler increase the maximum tractive force that could be produced between the wheels and ground

Answer 1

Image to question is attached.

Answer:

f₂ = 405 lb

Step-by-step explanation:

Given:

Coefficient of friction, u = 0.6

Lift coefficient for spoiler, c= 1.1

Speed, V = 200 mph => convert to ft/s, we have:

`200mi/hr * 5280mi * (1hr)/(3600s) = 293.3ft/s`

To find the new tractive force, we have:

f₂ = u*N₂ = uL

Where L = ½ PV²*c*A

`f_2 = 0.6 * (1)/(2) * 0.00238 * 293.3^2 * 1.1 * 1.5 * 4 = 405 lb`

The maximum tractive force that could be produced between the wheels and ground would be increased by 405 lb.

Answer 2

405 Ib

Step-by-step explanation:

the picture below shows the explanation to the problem. Its so explanatory and i hope it helps you