Question

Write the balanced chemical equation between H2SO4H2SO4 and KOHKOH in aqueous solution. This is called a neutralization reaction and will produce water and potassium sulfate. Phases are optional. balanced chemical equation: H2SO4+2KOH⟶K2SO4+2H2OH2SO4+2KOH⟶K2SO4+2H2O 0.750 L0.750 L of 0.470 M0.470 M H2SO4H2SO4 is mixed with 0.700 L0.700 L of 0.240 M0.240 M KOH.KOH. What concentration of sulfuric acid remains after eutralization?

Answer 1

0.185M sulfuric acid

Step-by-step explanation:

Based on the reaction:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

1 mole of sulfuric acid reacts with 2 moles of KOH

Initial moles of H₂SO₄ and KOH are:

H₂SO₄: 0.750L ₓ (0.470mol / L) = 0.3525 moles of H₂SO₄

KOH: 0.700L ₓ (0.240mol / L) = 0.168 moles of KOH

The moles of sulfuric acis that react with KOH are:

0.168mol KOH ₓ (1 mole H₂SO₄ / 2 moles KOH) = 0.0840 moles of sulfuric acid.

Thus, moles that remain are:

0.3525moles - 0.0840 moles = 0.2685 moles of sulfuric acid remains

As total volume is 0.700L + 0.750L = 1.450L, concentration is:

0.2685mol / 1.450L = 0.185M sulfuric acid