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The temperature of the surface of the Sun is 5500°C. show answer No Attempt 50% Part (a) What is the average kinetic energy, in joules, of hydrogen atoms on the surface of the Sun? KEave,sur = | sin() cos() tan() cotan() asin() acos() atan() acotan() sinh() cosh() tanh() cotanh() Degrees Radians π ( ) 7 8 9 HOME E ↑^ ^↓ 4 5 6 ← / * 1 2 3 → + - 0 . END √() BACKSPACE DEL CLEAR Grade Summary Deductions 0% Potential 100% Submissions Attempts remaining: 3 (4% per attempt) detailed view Hints: 4% deduction per hint. Hints remaining: 1 Feedback: 5% deduction per feedback. No Attempt No Attempt 50% Part (b) What is the average kinetic energy, in joules, of helium atoms in a region of the solar corona where the temperature is 6.00 × 105 K?

User Rpmartz
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Answer:

K = 4.43 10⁻¹⁸ J

Step-by-step explanation:

The energy of the atoms on the surface of the sun is ‘

E = K + U

where the potential energy is given by

U = - k q² / r

the total energy is given by the thermal energy

E = k T

let's substitute in the first equation

k T = K - k e² / r

K = kT + k e2 / r

the constant are worth

k the Boltzmann constant k = 1,381 10-23 J / K

k the Coulomb cosntnate k = 8.99 109 N m2 / C2

e the charge of the electron e = 1.6 10-19 C

r the radius of the hydrogen atom r = 0.0529 10-9 m

let's calculate

K = 1.381 10⁻²³ 5500 + 8.99 10⁹ (1.6 10⁻¹⁹)² / 0.0529 10⁻⁹

K = 7.596 10⁻²⁰ + 4.35 10⁻¹⁸

K = 4.43 10⁻¹⁸ J

User Freespace
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