If 23.5 g of ammonia (NH3) is dissolved in 1.0 L of solution, what is the molarity?

asked Apr 5, 2023 33.6k views

7 votes

6.6k points

Please log in or register to add a comment.

3 votes

Answer:

1.38 M

Step-by-step explanation:

Need to use the Molarity equation M=n/L

23.5g/ 17.031g/mol NH3 = 1.38 moles

1.38 moles/ 1.0 L = 1.38 M

Sports answered Apr 10, 2023

6.6k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

7.9m questions

10.6m answers