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In the diagram shown on circle A, segment CD is tangent to the circle at point D. If CD=23 and CA = 28.

then which of the following is closest to mZC?

1 Answer

3 votes

Answer:

35°

Explanation:

The diagram is shown in the image attached.

A tangent is a line that intercepts at one unique point. When we have a tangent about a circle, an important results is that the tangent is perpendicular to the radius, because a radius can be seen as perpendicular to any point of the circle.

That means, the triangle formed ADC is a right triangle, because
\angle D= 90\°.

Now, we know that
CD=23 and
CA=28, which are leg and hypothenuse, respectively.

So, to find
m \angle C we just need to use trigonometric reasons, specifically, the cosine funtion, because it relates the adjacent leg and the hypothenuse.


cos(C)=(CD)/(CA)=(23)/(28) \\C=cos^(-1)((23)/(28) ) \approx 35 \°

Therefore, the measure of angle C is 35°, approximately.

In the diagram shown on circle A, segment CD is tangent to the circle at point D. If-example-1
User Elenita
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