Answer:
There is enough evidence to reject the manufacturer’s claim and the standardized test statistic z is -3.43
Explanation:
A manufacturer of sprinkler systems designed for fire protection claims that the average activating temperature is at least 135°F.
So, Null hypothesis:
![H_0:\mu \geq 135](https://img.qammunity.org/2021/formulas/mathematics/college/9ml4rthb8esb8y0epfzri927gno6qebxcg.png)
Alternate hypothesis :
![H_a:\mu <135](https://img.qammunity.org/2021/formulas/mathematics/college/k1oc009725mgx2ygg50e06q3c6wgrhsbcl.png)
To test this claim, you randomly select a sample of 32 systems and find the mean activation temperature to be 133°F.
x=133
n = 32
Population Standard deviation =
![\sigma = 3.3^(\circ)F](https://img.qammunity.org/2021/formulas/mathematics/college/3d9wfvxxkz5c9gwce7oyqtzwgi76edrdgc.png)
Formula :
![z=(x-\mu)/((\sigma)/(√(n)))](https://img.qammunity.org/2021/formulas/mathematics/college/kq8xzi76iw0tnbjbtcik4v8u9dcuoas2pe.png)
![z=(133-135)/((3.3)/(√(32)))\\\\z=-3.428](https://img.qammunity.org/2021/formulas/mathematics/college/ddlq7vhxej0x91wxkti230998ka1hboaxx.png)
z=-3.43
Refer the z table for p value
p value = 0.0003
![\alpha = 0.10](https://img.qammunity.org/2021/formulas/engineering/college/jps3unr82c4ioxfx6y9497rl6wkf1r013l.png)
p value < α
So, we failed to accept null hypothesis
Hence there is enough evidence to reject the manufacturer’s claim and the standardized test statistic z is -3.43