Answer:
Probability that both eggs are cracked is 0.0001.
Explanation:
We are given that the probability that an egg on a production line is cracked is 0.01.
Two eggs are selected at random from the production line.
The above situation can be represented through binomial distribution;
![P(X = r) = \binom{n}{r} * p^(r) * (1-p)^(n-r);x=0,1,2,3,.......](https://img.qammunity.org/2021/formulas/mathematics/middle-school/g6n6evp1c8ymu1g75potqf0hg7r3hcqg40.png)
where, n = number trials (samples) taken = 2 eggs
r = number of success = both eggs are cracked
p = probability of success which in our question is probability that
an egg on a production line is cracked, i.e; p = 0.01
Let X = Number of eggs on a production line that are cracked
So, X ~ Binom(n = 2, p = 0.01)
Now, Probability that both eggs are cracked is given by = P(X = 2)
P(X = 2) =
![\binom{2}{2} * 0.01^(2) * (1-0.01)^(2-2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yslr2df1vom8myesexxmtuaiutwwdddzr5.png)
=
![1* 0.01^(2) * 0.99^(0)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/fl7by5ng64asxrsbukfzerywuu8q9fgugr.png)
= 0.0001
Therefore, probability that both eggs are cracked is 0.0001.