Answer:
Step-by-step explanation:
The speed of sound in air to be 343 m/s.
Given:
distance 'd' = 5 m
L = 12 m
It can be concluded that path difference must be equal to half of the wavelength when person is observing destructive interference'y' at 1 m distance from the equidistant position
Since
λ/2 = yd/L
λ/2 = (1 x 5)/12
λ = 0.833m
Frequency of the sound is given by,
f = v / λ => 343 / 0.833
f=411.6 Hz