196k views
5 votes
Suppose a parabola has vertex (–8, –7) and also passes through the point (–7, –4). Write the equation of the parabola in vertex form.

a.y=(x+8)^2-7
b.y=3(x-8)^2-7
c.y=3(x+8)^2-7
d.y=3(x+8)^2+7

User SergVro
by
8.8k points

1 Answer

4 votes

We have been given that a parabola has vertex
(-8,-7) and also passes through the point
(-7,-4). We are asked to write the equation of the parabola in vertex form.

We know that vertex form of parabola in format
y=a(x-h)^2+k, where point (h,k) represents vertex of parabola.

Let us write equation of parabola using our given information as:


y=a(x-(-8))^2-7


y=a(x+8)^2-7

Now we will substitute the coordinates of point
(-7,-4) to solve for a as:


-4=a(-7+8)^2-7


-4=a(1)^2-7


-4=a-7


-4+7=a-7+7


3=a

Therefore, our required equation would be
y=3(x+8)^2-7 and option 'c' is the correct choice.

User JHowzer
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.