Which equation, when solved, results in a different value of x than the other three? * 12x - 40 = 20 -3x + 16 = 1 2x + 4 = 18 10x - 15 = 35

Question

asked Oct 25, 2021 107k views

1 Answer

Rasul · Answer 1 · 2021-10-30T08:41:59+0000

Answer: All of them have different values of x.

Explanation:

Solve each individually.

$12x-40=20\\12x=20-40\\12x=-20\\x=-(20)/(12)\\ x=-(5)/(3)$

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$-3x+16=1\\-3x=1-16\\-3x=-15\\x=(-15)/(-3)\\ x=5$

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$2x+4=18\\2x=18-4\\2x=14\\x=(14)/(2)\\ x=7$

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$10x-15=35\\10x=35+15\\10x=45\\x=(45)/(10)\\ x=(9)/(2)$