Question

Carbon monoxide (CO) reacts with hydrogen (H2) to form methane (CH4) and water (H2O).

Upper C upper O (g) plus 3 upper H subscript 2 (g) double-headed arrow upper C upper H 4 (g) plus upper H subscript 2 upper O (g).

The reaction is at equilibrium at 1,000 K. The equilibrium constant of the reaction is 3.90. At equilibrium, the concentrations are as follows.

[CO] = 0.30 M
[H2] = 0.10 M
[H2O] = 0.020 M

What is the equilibrium concentration of CH4 expressed in scientific notation?
.0059
5.9 x 10-2
0.059
5.9 x 102

Answer 1

B

Step-by-step explanation:

Answer 2

5.9x10^-2 M

Step-by-step explanation:

Step 1:

Data obtained from the question. This includes the following:

Concentration of CO, [CO] = 0.30 M

Concentration of H2, [H2] = 0.10 M

Concentration of H2O, [H2O] = 0.020 M

Equilibrium constant, K = 3.90

Concentration of CH4, [CH4] =..?

Step 2:

The balanced equation for the reaction. This is given below:

CO(g) + 3H2(g) <=> CH4(g) + H2O(g)

Step 3:

Determination of the concentration of CH4.

The expression for equilibrium constant of the above equation is given below:

K = [CH4] [H2O] / [CO] [H2]^3

3.9 = [CH4] x 0.02/ 0.3 x (0.1)^3

Cross multiply to express in linear form

[CH4] x 0.02= 3.9 x 0.3 x (0.1)^3

Divide both side by 0.02

[CH4] = 3.9 x 0.3 x (0.1)^3 /0.02

[CH4] = 5.9x10^-2 M

Therefore, the equilibrium concentration of CH4 is 5.9x10^-2 M