Question

How many moles of molecular oxygen will be needed for the complete combustion of 100.0 g of sulfur dioxide? The product of this reaction is sulfur trioxide

Answer 1

0.7804

Step-by-step explanation:

Answer 2

0.78 mol O2

Step-by-step explanation:

2SO2 + O2 -> 2 SO3

64 g SO2 -> 1 mol SO2

100 g SO2 -> x

x= (100 g SO2 * 1 mol SO2)/64 g SO2 x=1.56 mol SO2

1 mol O2 -> 2 mol SO2

x -> 1.56 mol SO2

x= (1.56 mol SO2 * 1 mol O2)/2 mol SO2 x=0.78 mol O2