Question

What mass of H₂SO₄ would be required to react with 0.75 mol of NaOH? *

10 points
Captionless Image
13 g
19 g
26 g
37 g

Answer 1

= 37 g

Step-by-step explanation:

H₂SO₄ + 2NaOH ----> Na₂SO₄ + 2H₂O

2 moles of NaOH react with 1 mole of H₂SO₄

0.75 moles of NaOH will react with (0.75 / 2)×1

= 0.375 moles of H₂SO₄.

Formular mass of H₂SO₄ = (1×2)+32+(16×4) = 98g

1 mole of H₂SO₄ weighs 98g

0.375 moles of H₂SO₄ will weigh ( 0.375×98)g

= 36.7g = 37g of H₂SO₄