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Solve 11b^2-9=-68 using the square root method

1 Answer

4 votes

Answer:

b=i*
\sqrt{(59)/(11) } or -i*
\sqrt{(59)/(11) }

Explanation:

11b^2-9=-68

11b^2=-59

b^2=-59/11

b=i*
\sqrt{(59)/(11) } or -i*
\sqrt{(59)/(11) }

"i" in this case is an imaginary number, equal to
√(-1\\)

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